Question

I need to convert an ASCII string like… “hello2” into it’s decimal and or hexadecimal representation (a numeric form, the specific kind is irrelevant). So, “hello” would be : 68 65 6c 6c 6f 32 in HEX. How do I do this in C++ without just using a giant if statement?

EDIT: Okay so this is the solution I went with:

int main()
{
    string c = "B";
    char *cs = new char[c.size() + 1];
    std::strcpy ( cs, c.c_str() );
    cout << cs << endl;

    char a = *cs;
    int as = a;
    cout << as << endl;
    return 0;
}

Answer 1

You can use printf() to write the result to stdout or you could use sprintf / snprintf to write the result to a string. The key here is the %X in the format string.

#include <cstdio>
#include <cstring>
int main(int argc, char **argv)
{
    char *string = "hello2";
    int i;

    for (i = 0; i < strlen(string); i++)
        printf("%X", string[i]);

    return 0;
}

If dealing with a C++ std::string, you could use the string’s c_str() method to yield a C character array.