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Home/ Questions/Q 9012037
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T02:53:47+00:00 2026-06-16T02:53:47+00:00

I need to convert const_iterator into a type that I can do int and

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I need to convert const_iterator into a type that I can do int and string operations to.
results[1] contains the text from the regex_search that I need to work with.
I’ve spent a couple hours already trying cast into a workable format, no success…

boost::match_results<std::string::const_iterator> results;
      boost::regex ex(pattern, boost::regex::perl);
      if(boost::regex_search(line, results, ex))
        (results[1] > 10) ? cout << "Fail" : cout << "Pass";

Thanks,
Joe

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  1. Editorial Team
    Editorial Team
    2026-06-16T02:53:48+00:00Added an answer on June 16, 2026 at 2:53 am

    You could create an std::string out of a match result of const string iterators like this:

    std::string result_string( results[1].first, results[1].second );
    

    …or simply:

    std::string result_string = results[1].str();
    

    You can coerce the string to an int like this:

    int result_int = boost::lexical_cast< int >( result_string );
    

    …or, as pointed by @Jonathan Wakely, if you are using C++11:

    int result_int = std::stoi( result_string );
    
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