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Home/ Questions/Q 7011101
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T22:05:02+00:00 2026-05-27T22:05:02+00:00

I need to convert specific XML attribute into XML element. The input XML: <?xml

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I need to convert specific XML attribute into XML element.
The input XML:

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<filter query="select" name="some name"/>

My desire output looks like this:

<?xml version="1.0" encoding="UTF-8"?>
    <filter name="some name">
    <query>select</query>
</filter>

I’m using the following XSLT:

<?xml version="1.0" encoding="UTF-8"?>
   <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"      xmlns="http://www.w3.org/1999/xhtml">
   <xsl:strip-space elements="*"/>
   <xsl:output indent="yes"/>

   <xsl:template match="node()|@*">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
   </xsl:template>

   <xsl:template match="/filter/@query">
        <xsl:element name="{name(.)}">
            <xsl:value-of select="."/>
        </xsl:element>
   </xsl:template>
</xsl:stylesheet>

However when I apply this XSLT to the provided example the name attribute disappears:

<?xml version="1.0" encoding="UTF-8"?>
<filter>
    <query>select</query>
</filter>

If I change the attributes ordering, i.e. put ‘name’ before ‘query’ everything works perfectly.
I try to solve it but my XSLT knowledge is very limited. Please help. Thanks in advance.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T22:05:03+00:00Added an answer on May 27, 2026 at 10:05 pm

    This should give you the required output:

    <?xml version="1.0" encoding="UTF-8"?>
       <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
       <xsl:strip-space elements="*"/>
       <xsl:output indent="yes"/>
    
       <xsl:template match="node()|@*">
            <xsl:copy>
                <xsl:apply-templates select="@*|node()"/>
            </xsl:copy>
       </xsl:template>
    
       <!-- match the filter element -->
       <xsl:template match="filter">
         <!-- output a filter element -->
         <xsl:element name="filter">
           <!-- add the name attribute, using the source name attribute value -->
           <xsl:attribute name="name">
             <xsl:value-of select="@name"/>
           </xsl:attribute>
           <!-- add the query child element, using the source query attribute value -->
           <xsl:element name="query">
             <xsl:value-of select="@query"/>
           </xsl:element>
         </xsl:element>
       </xsl:template>
    
    </xsl:stylesheet>
    
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