Question

I need to convert symbols to bits so that every 2 symbols = 1 byte = 8 bits.
For example, if user input is RR then there should be 00001100 as result. (just an example)

Answer 1

So, if I understood your question, there’re two options to resolve then: The easy or the hard way.

Easy:

• First of all, you need know if the literal to be used is a hexademical value.
• You can create a Sorted map that’s represent the ASCII table, using the key 0-9 | A-H and the value represent your binary number.

Example:

SortedMap<Character, String>
lo_binary = new TreeMap<Character, String>();
lo_binary.put('0', "0000");
lo_binary.put('1', "0001");
lo_binary.put('2', "0010");
lo_binary.put('3', "0011");
lo_binary.put('4', "0100");
lo_binary.put('5', "0101");
lo_binary.put('6', "0110");
lo_binary.put('7', "0111");
lo_binary.put('8', "1000");
lo_binary.put('9', "1001");
lo_binary.put('A', "1010");
lo_binary.put('B', "1011");
lo_binary.put('C', "1100");
lo_binary.put('D', "1101");
lo_binary.put('E', "1110");
lo_binary.put('F', "1111");

• Read the two symbols and try find your binary code into Sorted Map.

• Stores the result into a String

  String ls_symbols = “AA”;
  String ls_result = ” “;

  for (int ln=0; ln < ls_symbols.lenght(); ln++) {
  ls_result += lo_binary.get(ls_symbols.charAt(ln));
  }

  System.out.println(ls_result); // AA -> 10101010

Hard:

• First of all, you need know if the literal to be used is a hexademical value.
• Converts a literal with hexadecimal characters to byte[].
• Converts the byte[] to boolean[]
• The result is true = 1 and false = 0

Example:

// Do you have a literal A. This literal represents in binary the value 1010. Do you have // use the operator >>> and & to change the binary value to boolean value

1010
boolean = (1010 & 1000) == 1000 // (1000 = represents 0x80)
boolean = true (1);

1010 >>> 0100
boolean = (0100 & 1000) == 0000
boolean = false (0);

0100 >>> 1000
boolean = (1000 & 1000) == 1000
boolean = true (1);

1000 >>> 0000
boolean = (0000 & 1000) == 0000
boolean = false (0);