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Home/ Questions/Q 7710647
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T01:10:43+00:00 2026-06-01T01:10:43+00:00

I need to convert the following java method to scala and am having difficulty

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I need to convert the following java method to scala and am having difficulty because scala doesn’t allow you to return values in the middle of methods. Could someone give me a hand or at least a start on how to convert this:

public boolean isAllowed(String method, String path, Map<String,String> apiUrlMap) {

    if (apiUrlMap != null) {
        Set<Entry<String, String>> apiSet = apiUrlMap.entrySet();

        for (Entry<String, String> apiUrl : apiSet) {
            String aUrl = apiUrl.getKey();
            String aMeth = apiUrl.getValue();
            if (aUrl.equals("#")) {
                if (aMeth.contains(method)) {
                    return true;
                }
            }

            if (aUrl.endsWith("#")) {
                String testUrl = aUrl.replaceFirst("/#", "");
                if (path.startsWith(testUrl)) {
                    if (aMeth.contains(method)) {
                        return true;
                    }
                }
            }

            if (aUrl.equals(path) || path.equals(aUrl +"/")) {
                if (aMeth.contains(method)) {
                    return true;
                }
            }

        }
    }

    return false;
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T01:10:44+00:00Added an answer on June 1, 2026 at 1:10 am

    Having a quick go at it (not tested)

    def isAllowed(method:String, path:String, apiUrlMap:Map[String,String]) = 
      apiUrlMap exists { case (aUrl, aMeth) => {
            aUrl.equals("#") ||  
            aUrl.endsWith("#") && path.startsWith(aUrl.replaceFirst("/#", "")) || 
            (aUrl.equals(path) || path.equals(aUrl +"/"))
          } && aMeth.contains(method)
        }
    
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