Question

I need to create a search query that finds all users with specified hourly rates. The users have hourly rate ranges such as $55/h to $75/h. A site visitor will search for these users with another range such as $40/h to $60, which should display all overlapping registered users.

The old working plain string query was:

(users.hour_price_low BETWEEN :low_price AND :high_price OR hour_price_high BETWEEN :low_price AND :high_price).

I need to refactor this to searchable in an array query. My starting point for the refactor was this RailsCast.

I have modified the methods to accomodate OR clauses, no problems there.

##This is where I am getting hung up.  I can't get the syntax correct.##

def low_price_or_conditions
    ["users.hour_price_low BETWEEN ?", price_low..price_high] unless price.blank?
end

def high_price_or_conditions
    ["users.hour_price_high BETWEEN ?", price_low..price_high] unless price.blank?
end

Finally:

@users = User.where(conditions)

Which outputs this error:

Mysql::Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '61,62,63,64,65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80 OR users.hour_pr' at line 1: SELECT `users`.* FROM `users` WHERE (users.hour_price_low BETWEEN 60,61,62,63,64,65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80 OR users.hour_price_high BETWEEN 60,61,62,63,64,65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80)

I am open to any suggestions. Thanks!

Answer 1

Skip the range, and just use the between clause as you were previously.

ie

["users.hour_price_low BETWEEN ? AND ?", price_low, price_high]