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Home/ Questions/Q 7810479
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T03:47:54+00:00 2026-06-02T03:47:54+00:00

I need to create a xml shape drawable that draws a rectangle without the

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I need to create a xml shape drawable that draws a rectangle without the top-line (a “u-form”). What I am able to do is draw a rectangle, like so:

<?xml version="1.0" encoding="UTF-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android"
android:shape="rectangle" >

<solid android:color="@color/detailrow_bg_normal" />

<corners
    android:bottomLeftRadius="0dp"
    android:bottomRightRadius="0dp"
    android:radius="1dp"
    android:topLeftRadius="10dp"
    android:topRightRadius="10dp" />

<padding
    android:bottom="2dip"
    android:left="1.5dip"
    android:right="1.5dip"
    android:top="8dip" />

<stroke
    android:width="1dip"
    android:color="@color/detailtable_border" />

But how – if possible, can I define the same shape without the top (or bottom) line?

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  1. Editorial Team
    Editorial Team
    2026-06-02T03:47:58+00:00Added an answer on June 2, 2026 at 3:47 am

    You could try using a layer-list. See if something like this would work:

    <layer-list xmlns:android="http://schemas.android.com/apk/res/android" >
        <item>
          <shape android:shape="rectangle">
                <solid android:color="@color/detailtable_border" />
            </shape>
       </item>
    
       <item android:left="1.5dp" android:right="1.5dp" android:bottom="2dp">
          <shape android:shape="rectangle">
            <solid android:color="@color/detailrow_bg_normal" />
          </shape>
       </item>
    </layer-list>
    

    This (should) fill the rectangle with the border color, then overlay it with the default background color, leaving the appropriate amount of the right/left/bottom border color showing.

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