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Asked: May 10, 20262026-05-10T18:00:47+00:00 2026-05-10T18:00:47+00:00

I need to create at runtime instances of a class that uses generics, like

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I need to create at runtime instances of a class that uses generics, like class<T>, without knowing previously the type T they will have, I would like to do something like that:

public Dictionary<Type, object> GenerateLists(List<Type> types) {     Dictionary<Type, object> lists = new Dictionary<Type, object>();      foreach (Type type in types)     {         lists.Add(type, new List<type>()); /* this new List<type>() doesn't work */     }      return lists; } 

…but I can’t. I think it is not possible to write in C# inside the generic brackets a type variable. Is there another way to do it?

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  1. 2026-05-10T18:00:47+00:00Added an answer on May 10, 2026 at 6:00 pm

    You can’t do it like that – the point of generics is mostly compile-time type-safety – but you can do it with reflection:

    public Dictionary<Type, object> GenerateLists(List<Type> types) {     Dictionary<Type, object> lists = new Dictionary<Type, object>();      foreach (Type type in types)     {         Type genericList = typeof(List<>).MakeGenericType(type);         lists.Add(type, Activator.CreateInstance(genericList));     }      return lists; } 
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