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Home/ Questions/Q 7011247
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T22:06:09+00:00 2026-05-27T22:06:09+00:00

I need to create something like this: my $valueref = { 1 => 1,

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I need to create something like this:

my $valueref = {
    1 => 1,
    2 => 2,
    3 => 3,
    4 => 4
};

Based on certain conditions, it might be up to 40, or 50 or 60. In each case it would be consecutive integers, as show in the example. Once created, it would never be changed, simply passed to a preexisting subroutine. Since both the keys and the values will be consecutive, I could also create the hash using a for loop. I was curious what would be the fastest and/or most efficient way to create the hash? Or if there was yet another way it could be done?

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  1. Editorial Team
    Editorial Team
    2026-05-27T22:06:10+00:00Added an answer on May 27, 2026 at 10:06 pm

    Using map would suffice:

    my $valueref = { map { $_ => $_ } 1 .. 40 };
    

    Though one might note here that this is actually an array…

    my @array = 0 .. 40;
    

    So $valueref->{$n} is actually $array[$n]. I don’t know if there is any benefit to using a hash in this case.

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