I need to create two threads that strictly alternates. Here is sample code what I use:
#include <Windows.h>
#include <iostream>
using std::cout;
using std::endl;
HANDLE g_hMutex1;
HANDLE g_hMutex2;
DWORD WINAPI ThreadFunc1(LPVOID lpParam);
DWORD WINAPI ThreadFunc2(LPVOID lpParam);
int main(void)
{
int nCalcNumber = 10;
DWORD dwThreadId;
HANDLE pThreadHandles[2];
g_hMutex1 = CreateMutex(NULL, FALSE, NULL);
g_hMutex1 = CreateMutex(NULL, FALSE, NULL);
pThreadHandles[0] = CreateThread(
NULL,
0,
ThreadFunc1,
static_cast<void*>(&nCalcNumber),
0,
&dwThreadId);
pThreadHandles[1] = CreateThread(
NULL,
0,
ThreadFunc2,
static_cast<void*>(&nCalcNumber),
0,
&dwThreadId);
WaitForMultipleObjects(2, pThreadHandles, TRUE, INFINITE);
CloseHandle(pThreadHandles[0]);
CloseHandle(pThreadHandles[1]);
CloseHandle(g_hMutex1);
CloseHandle(g_hMutex2);
return 0;
}
DWORD WINAPI ThreadFunc1(LPVOID lpParam)
{
int* nCalcNumber = static_cast<int*>(lpParam);
for (int i = 0; i < *nCalcNumber; i++)
{
WaitForSingleObject(g_hMutex1, INFINITE);
cout << "Func 1" << endl;
ReleaseMutex(g_hMutex1);
}
return 0;
}
DWORD WINAPI ThreadFunc2(LPVOID lpParam)
{
int* nCalcNumber = static_cast<int*>(lpParam);
for (int i = 0; i < *nCalcNumber; i++)
{
WaitForSingleObject(g_hMutex1, INFINITE);
cout << "Func 2" << endl;
ReleaseMutex(g_hMutex1);
}
return 0;
}
And a result, which I expect to receive:
Func 1
Func 2
Func 1
Func 2
Func 1
Func 2
...and so one
What should be added to get the desired result. Can I use for that the second mutex?
If you can use
semaphore: You can usesemaphoreinstead ofmutex, it’s easy to use same asmutex.This code works fine: