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Editorial Team
Asked: May 13, 20262026-05-13T09:45:40+00:00 2026-05-13T09:45:40+00:00

I need to display all the IP addresses from my local computer, using the

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I need to display all the IP addresses from my local computer, using the C language. How can this be done?

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  1. Editorial Team
    Editorial Team
    2026-05-13T09:45:40+00:00Added an answer on May 13, 2026 at 9:45 am
    #include <stdio.h>
    #include <stropts.h>
    #include <sys/socket.h>
    #include <sys/ioctl.h>
    #include <linux/netdevice.h>
    #include <arpa/inet.h>
    #include <netinet/in.h>
    #include <unistd.h>
    
    int print_addresses(const int domain)
    {
      int s;
      struct ifconf ifconf;
      struct ifreq ifr[50];
      int ifs;
      int i;
    
      s = socket(domain, SOCK_STREAM, 0);
      if (s < 0) {
        perror("socket");
        return 0;
      }
    
      ifconf.ifc_buf = (char *) ifr;
      ifconf.ifc_len = sizeof ifr;
    
      if (ioctl(s, SIOCGIFCONF, &ifconf) == -1) {
        perror("ioctl");
        return 0;
      }
    
      ifs = ifconf.ifc_len / sizeof(ifr[0]);
      printf("interfaces = %d:\n", ifs);
      for (i = 0; i < ifs; i++) {
        char ip[INET_ADDRSTRLEN];
        struct sockaddr_in *s_in = (struct sockaddr_in *) &ifr[i].ifr_addr;
    
        if (!inet_ntop(domain, &s_in->sin_addr, ip, sizeof(ip))) {
          perror("inet_ntop");
          return 0;
        }
    
        printf("%s - %s\n", ifr[i].ifr_name, ip);
      }
    
      close(s);
    
      return 1;
    }
    
    int main(int argc, char *argv[])
    {
      int domains[] = { AF_INET, AF_INET6 };
      int i;
    
      for (i = 0; i < sizeof(domains) / sizeof(domains[0]); i++)
        if (!print_addresses(domains[i]))
          return 1;
    
      return 0;
    }
    
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