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Home/ Questions/Q 981085
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T04:29:09+00:00 2026-05-16T04:29:09+00:00

I need to do one thing if args is integer and ather thing if

  • 0

I need to do one thing if args is integer and ather thing if args is string.

How can i chack type? Example:

def handle(self, *args, **options):

        if not args:
           do_something()
        elif args is integer:
           do_some_ather_thing:
        elif args is string: 
           do_totally_different_thing()
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  1. Editorial Team
    Editorial Team
    2026-05-16T04:29:10+00:00Added an answer on May 16, 2026 at 4:29 am

    First of, *args is always a list. You want to check if its content are strings?

    import types
    def handle(self, *args, **options):
        if not args:
           do_something()
        # check if everything in args is a Int
        elif all( isinstance(s, types.IntType) for s in args):
           do_some_ather_thing()
        # as before with strings
        elif all( isinstance(s, types.StringTypes) for s in args):
           do_totally_different_thing()
    

    It uses types.StringTypes because Python actually has two kinds of strings: unicode and bytestrings – this way both work.

    In Python3 the builtin types have been removed from the types lib and there is only one string type.
    This means that the type checks look like isinstance(s, int) and isinstance(s, str).

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