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Home/ Questions/Q 349851
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T11:29:49+00:00 2026-05-12T11:29:49+00:00

I need to do the following in Python. I want to spawn a process

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I need to do the following in Python. I want to spawn a process (subprocess module?), and:

  • if the process ends normally, to continue exactly from the moment it terminates;
  • if, otherwise, the process “gets stuck” and doesn’t terminate within (say) one hour, to kill it and continue (possibly giving it another try, in a loop).

What is the most elegant way to accomplish this?

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  1. Editorial Team
    Editorial Team
    2026-05-12T11:29:49+00:00Added an answer on May 12, 2026 at 11:29 am

    The subprocess module will be your friend. Start the process to get a Popen object, then pass it to a function like this. Note that this only raises exception on timeout. If desired you can catch the exception and call the kill() method on the Popen process. (kill is new in Python 2.6, btw)

    import time
    
    def wait_timeout(proc, seconds):
        """Wait for a process to finish, or raise exception after timeout"""
        start = time.time()
        end = start + seconds
        interval = min(seconds / 1000.0, .25)
    
        while True:
            result = proc.poll()
            if result is not None:
                return result
            if time.time() >= end:
                raise RuntimeError("Process timed out")
            time.sleep(interval)
    
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