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Editorial Team
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Asked: 2026-05-25T03:02:01+00:00

I need to encode the body of my POST request but I don´t know

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I need to encode the body of my POST request but I don´t know which one to use.
I´m having a trouble with changing ´(´ into %28.
I was using so far NSUTF8StringEncoding, NSISOLatin1StringEncoding, NSISOLatin2StringEncoding. Non of them works.

The name of the parameter I have to send is:

monitoring_report[monitoring_report_time(1i)]=

which sould be transformed to:

monitoring_report%5monitoring_report_time%281i%29%5D=

and what I get is:

monitoring_report%5Bmonitoring_report_time(1i)%5D=
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1 Answer

  1. Editorial Team

    Use the Core Foundation function CFURLCreateStringByAddingPercentEscapes which has a legalURLCharactersToBeEscaped parameter. Parenthesis in URLs are legal which is why they’re not escaped by default.

    Example:

    NSString *input = @"monitoring_report[monitoring_report_time(1i)]=";
NSString *output = [(NSString *)CFURLCreateStringByAddingPercentEscapes(kCFAllocatorDefault, (CFStringRef)input, NULL, CFSTR("()"), kCFStringEncodingUTF8) autorelease];
NSLog(@"%@", output); // monitoring_report%5Bmonitoring_report_time%281i%29%5D=
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