Question

I need to extract a randomly generated part of an URL for a Selenium Test in Java.

When the browser opens a page, e.g.:

/edit_person.html?id=eb58cea3a3772ff656987792eb0a8c0f

then I’m able to show the url with:

String url = driver.getCurrentUrl();

but now I need to get only the randomly generated ID after the equals sign.

How do I extract the value of parameter id once I have the entire URL as a string in variable url?

Answer 1

This is how managed to solve the problem:

String url = driver.getCurrentUrl();
        URL aURL = new URL(url);
        url = aURL.getQuery();
        String[] id = url.split("=");
        System.out.println(id[1]);  

Thanks to Jarrod Roberson!