Question

I need to extract the filename from a path (a string):

e.g.,
“C:\folder\folder\folder\file.txt” = “file” (or even “file.txt” to get me started)

Essentially everything before and including the last \

I’ve heard of using wildcards in place of Regex (as it’s an odd implementation in VBA?) but can’t find anything solid.

Cheers in advance.

Answer 1

Thanks to kaveman for the help. Here is the full code I used to remove both the path and the extension (it is not full proof, does not take into consideration files that contain more than 2 decimals eg. *.tar.gz)

sFullPath = "C:\dir\dir\dir\file.txt"   
sFullFilename = Right(sFullPath, Len(sFullPath) - InStrRev(sFullPath, "\"))
sFilename = Left(sFullFilename, (InStr(sFullFilename, ".") - 1))

sFilename = “file”