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Home/ Questions/Q 8956455
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T14:47:25+00:00 2026-06-15T14:47:25+00:00

I need to find a file in a directory that matches a certain condition.

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I need to find a file in a directory that matches a certain condition. For example, I know the file name starts with ‘123-‘, and ends with .txt, but I have no idea what is in between the two.

I’ve started the code to get the files in a directory and the preg_match, but am stuck. How can this be updated to find the file I need?

$id = 123;

// create a handler for the directory
$handler = opendir(DOCUMENTS_DIRECTORY);

// open directory and walk through the filenames
while ($file = readdir($handler)) {

  // if file isn't this directory or its parent, add it to the results
  if ($file !== "." && $file !== "..") {
    preg_match("/^".preg_quote($id, '/')."\\-(.+)\\.txt$/" , $file, $name);

    // $name = the file I want
  }

}

// tidy up: close the handler
closedir($handler);
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T14:47:26+00:00Added an answer on June 15, 2026 at 2:47 pm

    I wrote up a little script here for ya, Cofey. Try this out for size.

    I changed the directory for my own test, so be sure to set it back to your constant.

    Directory Contents:

    • 123-banana.txt
    • 123-extra-bananas.tpl.php
    • 123-wow_this_is_cool.txt
    • no-bananas.yml

    Code:

    <pre>
    <?php
    $id = 123;
    $handler = opendir(__DIR__ . '\test');
    while ($file = readdir($handler))
    {
        if ($file !== "." && $file !== "..")
        {
          preg_match("/^({$id}-.*.txt)/i" , $file, $name);
          echo isset($name[0]) ? $name[0] . "\n\n" : '';
        }
    }
    closedir($handler);
    ?>
    </pre>
    

    Result:

    123-banana.txt
    
    123-wow_this_is_cool.txt
    

    preg_match saves its results to $name as an array, so we need to access by it’s key of 0. I do so after first checking to make sure we got a match with isset().

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