Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8216763
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 7, 20262026-06-07T12:14:37+00:00 2026-06-07T12:14:37+00:00

I need to find a way to work out the length and the width

  • 0

I need to find a way to work out the length and the width of the image (which is a .jpg) I have the length of the file but it is not useful because I want to make an array to store information about each pixel of the image file I am using.

public void getImageData(){
    File f= new File("myPicture.jpg");
    this.length = (int) f.length();
        System.out.println("length of file = " + length);
        BufferedImage image = null;
        try {
            image = ImageIO.read(f);
            } 
        catch (IOException e) {

            e.printStackTrace();
            }

Help much appreciated!

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-07T12:14:39+00:00Added an answer on June 7, 2026 at 12:14 pm

    Once you get the BufferedImage, you can just call the properties getWidth() and getHeight() on it:

    int imageWidth = image.getWidth();
    int imageHeight = image.getHeight();
    

    Hope this helps.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I need to find a way to join two XML files when they have
I am using primefaces datatable with clickable rows and I need to find way
I need to find a way to get actual page size in Google Chrome.
I need to find a way to check if the mouse moves in c#,
I need to find a way to spin off a thread from a static
I need to find a way to call a vb.net function in my aspx
I need to find some way of displaying a drop-down menu that depending on
I need to find a way to be notified when a System.IO.Pipe.NamedPipeServerStream opened in
I need to find a way to store 250 KB of plain text numbers
I need to find a way to use with(nolock) in every SELECT I do

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.