Question

I need to find names which contain three number 7 in the random order.

My attempt

We need to find first names which do not contain seven

ls | grep [^7] 

Then, we could remove these matches from the whole space

ls [remove] ls | grep [^7] 

The problem in my pseudo-code starts to repeat itself quickly.

How can you find the names which contain three 7s in the random order by AWK/Python/Bash?

[edit] The name can contain any number of letters and it contains words of three 7s.

Answer 1

Something like this:

printf '%s\n' *|awk -F7 NF==4