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Home/ Questions/Q 9240599
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T08:13:00+00:00 2026-06-18T08:13:00+00:00

I need to find the correct .offset()-position of a tabled TD-elements within a Drupal7-generated

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I need to find the correct .offset()-position of a tabled TD-elements within a Drupal7-generated HTML-site (jQuery_update installed). I use

        $('#contenttable td').each(function(){ 
            console.log($(this).offsetParent());
            console.log($(this).offset().left);
        });

within my

jQuery(function($) {
    //$(document).ready(function(){

of my script.js to get the offset().left-position but the console allways traces me ‘0’ for all TDs.

When I use the Safari Developer Console the output of

jQuery('#contenttable td:nth-child(2)').offset().left

is ‘1728’, so it seems to work at all. But why doesn’t it work from within my DOCUMENT.READY?

The .offsetParent() is BODY by the way… And changing some of the parents DIV’s position to absolute or relative didn’t give any change, too.
THNX!

edit: seems not to work for any element at all.

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  1. Editorial Team
    Editorial Team
    2026-06-18T08:13:01+00:00Added an answer on June 18, 2026 at 8:13 am

    Unfortunately, jQuery.offset does not work on hidden elements, because the browser doesn’t bother rendering them at all. So if possible, you need to make the element visible in order to get its offset. According to jquery: get the offset of hidden element , you should be able to call .show() on the table/content, get the desired offset, then call .hide() on it. This show/hide should not be apparent to the user, as it won’t repaint the page since it’s in the same execution event.

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