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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T08:33:02+00:00 2026-06-10T08:33:02+00:00

I need to generate a big array (or list) with random numbers ( 10⁵

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I need to generate a big array (or list) with random numbers ( 10⁵ numbers) . I was trying like that:

vet = random.sample(range(10),100000)

But when I try to run :

vet = random.sample(range(10),10000)

File “/usr/lib/python2.7/random.py”, line 320, in sample
raise ValueError(“sample larger than population”)
ValueError: sample larger than population

Any solution?

tkns

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  1. Editorial Team
    Editorial Team
    2026-06-10T08:33:04+00:00Added an answer on June 10, 2026 at 8:33 am

    What you want is

    [random.random() for _ in xrange(100000)]
    

    From the random module documentation:

    random.sample(population, k) Return a k length list of unique elements
    chosen from the population sequence. Used for random sampling without
    replacement.

    so when calling random.sample(range(10), 100000) you’re trying to extract 100000 unique elements in a sequence of length 10 which obviously can’t work.

    Note that

    • random.random() returns a floating value between [0 ; 1)
    • random.randrange([start], stop[, step]) returns a random element from the sequence range([start], stop[, step])
    • random.randint(a, b) returns an integer value in [a ; b]
    • when using random.sample, the equality len(population) >= k must hold
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