Question

I need to get 10 numbers from the user, and than calc the amount of times each digit is appear in all the numbers.

I wrote the next code:

# Reset variable
aUserNum=[]
aDigits=[]

# Ask the user for 10 numbers
for i in range(0,2,1):
    iNum = int(input("Please enter your number: "))
    aUserNum.append(iNum)

# Reset aDigits array
for i in range(0,10,1):
    aDigits.append(0)

# Calc the count of each digit
for i in range(0,2,1):
    iNum=aUserNum[i]
    print("a[i] ",aUserNum[i])
    while (iNum!=0):
        iLastNum=iNum%10
        temp=aDigits[iLastNum]+1
        aDigits.insert(iLastNum,temp)
        iNum=iNum//10

print(aDigits)

from the result, I can see that the temp is not working.
When I write this temp=aDigits[iLastNum]+1, Shouldn’t it say that the array in cell iLastNum will get the value of the cell +1?

thanks,
Yaniv

Answer 1

You can concatenate all the inputs to get a single string and use this with collections.Counter()

import collections
ct = collections.Counter("1234567890123475431234")
ct['3'] == 4
ct.most_common() # gives a list of tuples, ordered by times of occurrence