Question

I need to get a line position of file pointer from file like below.

string1\n
string2\n
string3\n

I’m reading file using this func.

function get() {
    $fp = fopen('example.txt', 'r');
    if (!$fp) {
        echo 'Error' . PHP_EOL;
    }
    while(!feof($fp)) {
        $string = trim(fgets($fp));
        if(!$string) {
                continue;
        } else {
            /*
            * Here I want to get a line number in this file
            */
            echo $string . PHP_EOL;
        }
    }
}

Answer 1

The simple solution is to use a counter.

function get() {

   // Line number counter
   $lncount = 0;

   $fp = fopen('example.txt', 'r');
   if (!$fp) {
       echo 'Error' . PHP_EOL;
   }
   while(!feof($fp)) {
      $string = trim(fgets($fp));

      // Increment line counter
      $lncount++;

      if(!$string) {
         continue;
      } else {

         // Show line
         echo "Current line: " . $lncount;

         echo $string . PHP_EOL;
      }
   }
}