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Home/ Questions/Q 4112934
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T22:15:33+00:00 2026-05-20T22:15:33+00:00

I need to get an array output as this [[1, 26], [3, 16], [3,

  • 0

I need to get an array output as this [[1, 26], [3, 16], [3, 17], [4, 27], [4, 26]] from the following php mysql code

    include("db.php");

$villa = $_GET['villa'];

$sql = mysql_query("SELECT unavailable_date_from, unavailable_date_to FROM villa WHERE name = '".$villa."'");
$json = "[";
    while($results = mysql_fetch_object($sql)){

        foreach ($results as $field => $value) {
            $a = explode("-", $value);

            $json = $json . '[' . $a[1] .','. $a[2] .'],';
        }

        $json = substr($json, 0, strlen($json)-1);

    }

$json = $json . ']';

echo $json;

The current code give the following result: [[03,08],[03,10][03,15],[03,20]]

Can somebody tell me how can I add that one comma between the second and third array element

Thanks

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  1. Editorial Team
    Editorial Team
    2026-05-20T22:15:33+00:00Added an answer on May 20, 2026 at 10:15 pm

    Move $json = substr($json, 0, strlen($json)-1); to be on the line before $json = $json . ']';.

    It will look like:

    if ($json != '[') $json = substr($json, 0, strlen($json)-1);
    $json = $json . ']';
    

    Kind of messy, but it will work. Edit: Using rtrim would be nicer:

    $json = rtrim($json, ',');
    $json = $json . ']';
    

    Here’s the full code:

    $json = '';
    while($results = mysql_fetch_object($sql)) {
        foreach ($results as $field => $value) {
            $a = explode("-", $value);
            $json .= '[' . $a[1] .','. $a[2] .'],';
        }
    }
    
    $json = '[' . rtrim($json,','). ']';
    
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