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Home/ Questions/Q 8482269
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T19:46:52+00:00 2026-06-10T19:46:52+00:00

I need to get the byte array out of everything I send to the

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I need to get the byte array out of everything I send to the output stream. But instead I get 4 bytes of rubbish. Why?

ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();
ObjectOutputStream objectOutputStream = new ObjectOutputStream(byteArrayOutputStream);
objectOutputStream.write(new byte[]{1,2,3,4,5,6,7,8,9});
byte[] original = byteArrayOutputStream.toByteArray(); 
System.out.println(Arrays.toString(original)); // why not [1,2,3,4,5,6,7,8,9]?
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T19:46:54+00:00Added an answer on June 10, 2026 at 7:46 pm

    There are several flaws in your code. First of all you should use writeObject():

    objectOutputStream.writeObject(new byte[]{1,2,3,4,5,6,7,8,9});
    

    then you should use symmetric ObjectInputStream for reading:

    final ObjectInputStream objectInputStream = new ObjectInputStream(
            new ByteArrayInputStream(
                    byteArrayOutputStream.toByteArray()
            )
    );
    byte[] original = (byte[]) objectInputStream.readObject();
    

    However if you already have a byte[], there is no point in using Java serialization to convert it to byte array (which it already is!) Just write and read it directly:

    ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();
    byteArrayOutputStream.write(new byte[]{1, 2, 3, 4, 5, 6, 7, 8, 9});
    final ByteArrayInputStream byteArrayInputStream = new ByteArrayInputStream(
        byteArrayOutputStream.toByteArray()
    );
    final byte[] original = new byte[9];
    byteArrayInputStream.read(original);
    System.out.println(Arrays.toString(original));
    
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