I need to go through an array from the middle outwords.
var array = [a,b,c,d,e];
I would need to print in this order:
c,d,b,e,a
I have already split the array in half, first going forward and then going backwards which is already an improvement, but I really need to go one on each side till the end of the array on each side.
Say I want to start in the middle. I have the following before the loop statement, condition, and I can’t seem to figure out the third part to switch one on each side incrementally.
for (var i = Math.floor(array.length/2); i >= 0 || i < array.length; i?){
//Do Something here.
}
Does anyone know how to do this?
Obviously I can’t seem to test this in this condition.
Thanks
I modified the answer below (Thanks so much) to come up with this function. It allows to start from anywhere in the array and choose the direction to go. I am sure it could be written more elegantly. There is also a safety for wrong index numbers.
var array = ["a", "b", "c", "d", "e"];
function processArrayMiddleOut(array, startIndex, direction){
if (startIndex < 0){
startIndex = 0;
}
else if ( startIndex > array.length){
startIndex = array.lenght-1;
};
var newArray = [];
var i = startIndex;
if (direction === 'right'){
var j = i +1;
while (j < array.length || i >= 0 ){
if (i >= 0) newArray.push(array[i]);
if (j < array.length) newArray.push(array[j]);
i--;
j++;
};
}
else if(direction === 'left'){
var j = i - 1;
while (j >= 0 || i < array.length ){
if (i < array.length) newArray.push(array[i]);
if (j >= 0) newArray.push(array[j]);
i++;
j--;
};
};
return newArray;
}
var result = processArrayMiddleOut(array, 2, 'left');
alert(result.toString());
Two counters, one going up, other going down:
http://jsfiddle.net/X9cQL/