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Home/ Questions/Q 6638141
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T23:23:59+00:00 2026-05-25T23:23:59+00:00

I need to go through this vector and delete the duplicates. A segmentation fault

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I need to go through this vector and delete the duplicates. A segmentation fault is occurring somewhere within this code. My guess is that it has something to do with deleting elements while the iterator is going through, but I don’t really have a concrete understanding of how these iterators are actually working yet, so I can’t figure it out.

vector<char *>::iterator iter;
for (iter = v->begin(); iter != v->end()-1; iter++ ){
    char *aString = *iter;
    int n = 1;
    while(iter+n != v->end()){
        int comparison = strcmp(aString, *(iter+n));
        if(comparison == 0){
            v->erase(iter + n);
        }
        n++;
    }
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T23:24:00+00:00Added an answer on May 25, 2026 at 11:24 pm

    Really, you just have a couple off-by-one problems here. You were comparing incorrectly against end() and incrementing n when you erased an element:

    for (iter = v->begin(); iter != v->end()-1; iter++ ){
                                      ^^^^^^^^
    

    And

    while(iter+n != v->end())
                 ^^
    

    The following will do what you want (and demonstrate that it works):

    int main()
    {
    
        std::vector<const char*> v (4, "this");
        std::vector<const char *>::iterator iter;
    
        for (iter = v.begin(); iter <  v.end(); iter++ ) {
            std::cout << *iter << " ";
        }
        std::cout << std::endl;
    
        for (iter = v.begin(); iter <  v.end(); iter++ ){
            const char *aString = *iter;
            int n = 1;
            while(iter+n < v.end()){
                int comparison = strcmp(aString, *(iter+n));
                if(comparison == 0){
                    v.erase(iter + n);
                }
                else
                    n++;
            }
        }
    
        for (iter = v.begin(); iter <  v.end(); iter++ ) {
            std::cout << *iter << std::endl;
        }
    
    }
    

    Output is:

    this this this this

    this

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