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Home/ Questions/Q 240187
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T20:38:45+00:00 2026-05-11T20:38:45+00:00

I need to grab an attribute of a custom HTML tag. I know this

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I need to “grab” an attribute of a custom HTML tag. I know this sort of question has been asked many times before, but regex really messes with my head, and I can’t seem to get it working.

A sample of XML that I need to work with is

<!-- <editable name="nameValue"> --> - content goes here - <!-- </editable> -->

I want to be able to grab the value of the name attribute, which in this case is nameValue. What I have is shown below but this returns a null value.

My regex string (for a Java app, hence the \ to escape the “) is:
"(.)?<!-- <editable name=(\".*\")?> -->.*<!-- </editable> -->(.)?"

I am trying to grab the attribute with quotation marks I figure this is the easiest and most general pattern to match. Well it just doesn’t work, any help will help me keep my hair.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-11T20:38:45+00:00Added an answer on May 11, 2026 at 8:38 pm

    I don’t think you need the (.)?s at the beginning and end of your regex. And you need to put in a capturing group for getting only the content-goes-here bit:

    This worked for me:

    String xml = "RANDOM STUFF<!-- <editable name=\"nameValue\"> --> - content goes here - <!-- </editable> -->RANDOM STUFF";
    Pattern p = Pattern.compile("<!-- <editable name=(\".*\")?> -->(.*)<!-- </editable> -->");
    Matcher m = p.matcher(xml);
    if (m.find()) {
        System.out.println(m.group(2));
    } else {
        System.out.println("no match found");
    }
    

    This prints:

     - content goes here - 
    
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