Question

I need to implement a function in a Windows batch script to get the LastIndexOf a character into a given string.

For example: Given the following string, I need to get the last index of character '/':

/name1/name2/name3
            ^

So I need to get the value:

12

Answer 1

(Note: I’m assuming Windows batch files because, frankly, I have only seen a single question asking for an actual DOS batch file here so far. Most people simply misattribute “DOS” to anything that has a window of gray-on-black monospaced text without knowing what they’re actually talking of.)

Just loop through it, updating the index as you go:

@echo off
setlocal enabledelayedexpansion
set S=/name1/name2/name3
set I=0
set L=-1
:l
if "!S:~%I%,1!"=="" goto ld
if "!S:~%I%,1!"=="/" set L=%I%
set /a I+=1
goto l
:ld
echo %L%