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Home/ Questions/Q 8568829
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T18:11:48+00:00 2026-06-11T18:11:48+00:00

I need to know how I can get the first element that is visible

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I need to know how I can get the first element that is visible in the browser view.

I am implementing a custom scroller. however when the user uses the mouse to scroll my custom scroller messes up. I need to find the visible divs in the visible area in the browser after scrolling, so I will be able to scroll to the right element.

here is the structure of my page:

<div class="page">

    <div id="scroller" class="news-scroller">
         <div ><span id="up"></span></div>
         <div ><span id="down"></span></div>
    </div>

    <div class="news">
    </div>
    <div class="news">
    </div>
    ....
</div>

I am using the scroller #up and #down to scroll to the previous or next div.news. (I use scrollTo plugin) but after using the mouse for scroll I need to understand which div.news is the first visible element in the page to reset my custom scroller.

Here is my code in case it helps:

var current = $(".news").eq(0);

$("#down").click(function(){
    if(current.next().size() > 0)
    {
        current = current.next();
        $.scrollTo("#"+current.attr("id"), 800);     

    }
    else  if(current.next().size() <= 0)
    {
        return
    }
});

$("#up").click(function(){
    if(current.prev().size() > 0)
    {
        current=current.prev();
        $.scrollTo("#"+current.attr("id"), 800);
    }
    else  if(current.prev().size() <= 0)
    {
        return;
}
});

and here is the example page.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-11T18:11:49+00:00Added an answer on June 11, 2026 at 6:11 pm

    Following code will tell you if element is completely visible.

    function isElementVisisble(element) {
              element = $(element);
               var parent = $(window);
            var containerLeft = parent.parent().scrollLeft();
            var containerRight = containerLeft + parent.parent().width();
            var elemLeft = element.offsetLeft;
            var elemRight = elemLeft + $(element).width();
            if (elemLeft < containerLeft || elemRight > containerRight) {
                return false;
            }
             return true;
        }
    

    You can use

       var firstVisibleElem;
        jQuery("*").each(function(){
            if(isElementVisisble(this)){
                 firstVisibleElem= this;
                  return false;
             }
        });
    
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