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Home/ Questions/Q 506857
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T06:44:39+00:00 2026-05-13T06:44:39+00:00

I need to load file to Lua’s variables. Let’s say I got name address

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I need to load file to Lua’s variables.

Let’s say I got

name address email

There is space between each. I need the text file that has x-many of such lines in it to be loaded into some kind of object – or at least the one line shall be cut to array of strings divided by spaces.

Is this kind of job possible in Lua and how should I do this? I’m pretty new to Lua but I couldn’t find anything relevant on Internet.

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  1. Editorial Team
    Editorial Team
    2026-05-13T06:44:39+00:00Added an answer on May 13, 2026 at 6:44 am

    To expand on uroc’s answer:

    local file = io.open("filename.txt")
    if file then
        for line in file:lines() do
            local name, address, email = unpack(line:split(" ")) --unpack turns a table like the one given (if you use the recommended version) into a bunch of separate variables
            --do something with that data
        end
    else
    end
    --you'll need a split method, i recommend the python-like version at http://lua-users.org/wiki/SplitJoin
    --not providing here because of possible license issues
    

    This however won’t cover the case that your names have spaces in them.

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