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Home/ Questions/Q 565493
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T12:52:41+00:00 2026-05-13T12:52:41+00:00

I need to load some ajax content after the fieldset with the class address.

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I need to load some ajax content after the fieldset with the class address. Using the code below it will replace the content of the .address with the ajax content.

    $('.accordion .head').click(function() {
    $(this).next().find('.address').after().load('http://test.dev/search/view/IdDaytrip/' + $(this).attr('id') + '.html');
    $(this).next().toggle('slow');
    return false;
}).next().hide();

<div style="display: none;">
<fieldset class="address">
<!-- AJAx CONTENT GOES HERE -->
    <ol>
        <li>Stadhouderskade 78</li>
        <li> Amsterdam-Zuid</li>
        <li>020-5239666</li>
    </ol>
</fieldset>
<!-- BUT THE AJAx CONTENT NEEDS TO GO HERE -->
<span class="tags">Tags: museum</span>
</div>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T12:52:41+00:00Added an answer on May 13, 2026 at 12:52 pm

    I usually do that this way:

    var clicked = $(this);
    $.get('http://test.dev/search/view/IdDaytrip/' + $(this).attr('id') + '.html',
    function(data){
        alert("Data Loaded: " + data);
        $(clicked).next().find('.address').after(data);
    });
    
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