Question

i need to make two different ajax calls and pass both the json data to another function. how can i do it using below ajax call format?

$.ajax({ 
    url:'',
    type:'GET',
    dataType: 'json',
    success: callme
}); 

$.ajax({ 
    url:'',
    type:'GET',
    dataType: 'json',
    success: callme
});

function callme(JSON1,JSON2){
}

Answer 1

This is the perfect use case for $.when (assuming you’re using jQuery):

var ajax1 = $.ajax({ 
    url:'',
    type:'GET',
    dataType: 'json'
});    

var ajax2 = $.ajax({ 
    url:'',
    type:'GET',
    dataType: 'json'
});

$.when(ajax1, ajax2).done(function(json1, json2) {
    // both requests succeeded    
}).fail(function(){
    // one or both requests failed
});

The done callback will only be called when both requests have completed successfully; the fail callback will be called if any request fails.