Question

I need to open a folder 3 levels down from where application executes (original example I had have some flaws):

        // find the path where the executable resides
        string dbPath = Application.StartupPath;

        // constructing the connection string - double slashes
        string connString = "Provider=Microsoft.Jet.OLEDB.4.0; Data Source="
            + dbPath + "\\..\\..\\..\\Magazines.accdb; User Id=admin; Password=";

But this will open:

C:\Documents and Settings\Server\Desktop\Lab 10\Lab 10\Lab 10\bin\Debug\..\..\..\Magazines.accdb

Original directory from where program starts:

C:\Documents and Settings\Server\Desktop\Lab 10\Lab 10\Lab 10\bin\Debug\

And I need it to be:

C:\Documents and Settings\Server\Desktop\Lab 10\Lab 10\Magazines.accdb

What is the proper was of doing this?

Answer 1

Use DirectoryInfo for evaluating the ‘..’

 var path = new DirectoryInfo (Path.Combine( "c:/bla", "../newBla")).FullName()

Also use Path.Combine for eased and more reliable combination.