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Home/ Questions/Q 6579841
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T15:56:55+00:00 2026-05-25T15:56:55+00:00

I need to order a list by status == Rejected and date ascending and

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I need to order a list by status == “Rejected” and date ascending and then by status == “Accepted” and date descending.

I am trying the following but I’m not sure how to go about this:

items
   .OrderBy(x => x.status == "Rejected") 
   .ThenBy(x => x.DateSubmitted)
   .ThenBy(x => x.status == "Accepted") 
   .ThenByDescending(x => x.DateSubmitted)
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T15:56:56+00:00Added an answer on May 25, 2026 at 3:56 pm

    You’re describing the task a bit awkward, which (I think) leads you to a slightly wrong implementation.

    I say:

    items
       .Where(x => x.status == "Rejected") 
       .OrderBy(x => x.DateSubmitted)
       .Concat(items.
           .Where(x => x.status == "Accepted") 
           .OrderByDescending(x => x.DateSubmitted));
    

    The main difference is that now, status other than “Rejected” or “Accepted” are not shown.
    However, I think it is what you intended. If you want the full set, consider using

    items
       .Where(x => x.status == "Rejected") 
       .OrderBy(x => x.DateSubmitted)
       .Concat(items.
           .Where(x => x.status != "Rejected") 
           .OrderByDescending(x => x.DateSubmitted));
    

    PS. This is also assuming Linq-To-Objects. I’m not very well-versed with Linq-to-EF or Linq-to-SQL

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