Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 3613704
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 18, 20262026-05-18T22:09:28+00:00 2026-05-18T22:09:28+00:00

I need to package a configuration file within a jar. the configuration file is

  • 0

I need to package a configuration file within a jar. the configuration file is under the root of the jar file.
However I got the following error:

Caused by: java.lang.IllegalArgumentException: URI is not hierarchical
at java.io.File.(Unknown Source)

File url = new File(MyClass.class.getClassLoader().getResource("my.conf").toURI());
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-18T22:09:28+00:00Added an answer on May 18, 2026 at 10:09 pm

    You should use getResourceAsStream() instead. If the file is embedded in your JAR the URI is most likely bundle:// URI

    InputStream is = this.getClass().getResourceAsStream("my.conf");
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

We need a mailing list package similar to Python Mailman . I'd use Mailman
I need to read a properties files that's buried in my package structure in
I'm need to choose a software package for installing software. NSIS and WiX seem
Explanation: Say package A is always built first and then package B. I need
Need to locate the following pattern: The letter I followed by a space then
I have installed a package from .rpm file and it is stored in /opt
I need to get the package name of an Android APK. I have tried
I need to define my android Estates class using simplexml package from an xml
When building a multi-framework package for Nuget you need to divide up the library
I need to build SSIS packages on a build machine, and do not want

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.