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Home/ Questions/Q 6017377
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T03:07:11+00:00 2026-05-23T03:07:11+00:00

I need to parse a JSON Response that looks like: {key1: value1, key2: value2,

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I need to parse a JSON Response that looks like:

{"key1": "value1", 
 "key2": "value2", 
 "key3": 
    {"childKey1": "childValue1", 
     "childKey2": "childValue2", 
     "childKey3": "childValue3" }
}

class Egg { 
    @SerializedName("key1")
    private String mKey1;

    @SerializedName("key2")
    private String mKey2;

    @SerializedName("key3")
    // ???
}

I’m reading through the Gson docs but cannot figure out how to properly deserialize a dictionary to a Map.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T03:07:12+00:00Added an answer on May 23, 2026 at 3:07 am

    Gson readily handles deserialization of a JSON object with name:value pairs into a Java Map.

    Following is such an example using the JSON from the original question. (This example also demonstrates using a FieldNamingStrategy to avoid specifying the serialized name for every field, provided that the field-to-element name mapping is consistent.)

    import java.io.FileReader;
    import java.lang.reflect.Field;
    import java.util.Map;
    
    import com.google.gson.FieldNamingStrategy;
    import com.google.gson.Gson;
    import com.google.gson.GsonBuilder;
    
    public class Foo
    {
      public static void main(String[] args) throws Exception
      {
        GsonBuilder gsonBuilder = new GsonBuilder();
        gsonBuilder.setFieldNamingStrategy(new MyFieldNamingStrategy());
        Gson gson = gsonBuilder.create();
        Egg egg = gson.fromJson(new FileReader("input.json"), Egg.class);
        System.out.println(gson.toJson(egg));
      }
    }
    
    class Egg
    {
      private String mKey1;
      private String mKey2;
      private Map<String, String> mKey3;
    }
    
    class MyFieldNamingStrategy implements FieldNamingStrategy
    {
      //Translates the Java field name into its JSON element name representation.
      @Override
      public String translateName(Field field)
      {
        String name = field.getName();
        char newFirstChar = Character.toLowerCase(name.charAt(1));
        return newFirstChar + name.substring(2);
      }
    }
    
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