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Home/ Questions/Q 3595064
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T19:48:07+00:00 2026-05-18T19:48:07+00:00

I need to parse a url to get a list of urls that link

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I need to parse a url to get a list of urls that link to a detail page. Then from that page I need to get all the details from that page. I need to do it this way because the detail page url is not regularly incremented and changes, but the event list page stays the same.

Basically:

example.com/events/
    <a href="http://example.com/events/1">Event 1</a>
    <a href="http://example.com/events/2">Event 2</a>

example.com/events/1
    ...some detail stuff I need

example.com/events/2
    ...some detail stuff I need
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  1. Editorial Team
    Editorial Team
    2026-05-18T19:48:08+00:00Added an answer on May 18, 2026 at 7:48 pm
    import urllib2
    from BeautifulSoup import BeautifulSoup
    
    page = urllib2.urlopen('http://yahoo.com').read()
    soup = BeautifulSoup(page)
    soup.prettify()
    for anchor in soup.findAll('a', href=True):
        print anchor['href']
    

    It will give you the list of urls. Now You can iterate over those urls and parse the data.

    • inner_div = soup.findAll("div", {"id": "y-shade"})
      This is an example. You can go through the BeautifulSoup tutorials.
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