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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T21:20:36+00:00 2026-05-26T21:20:36+00:00

I need to parse Apache log file to look for specific suspicious patterns (like

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I need to parse Apache log file to look for specific suspicious patterns (like SQL injections).

For example I’m looking for id='%20or%201=1;

I am using grep to check the log file for this pattern (and others) and because these logs are huge it takes a long amount of time

Here my command:

grep 'id=' Apache.log | egrep "' or|'%20"

Is there a better or a faster method or command I need use to make the search faster?

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  1. Editorial Team
    Editorial Team
    2026-05-26T21:20:36+00:00Added an answer on May 26, 2026 at 9:20 pm

    For starters, you don’t need to pipe your grep output to egrep. egrep provides a superset of grep‘s regular expression parsing, so you can just do this:

    egrep "id='( or|%20)'" apache.log
    

    Calling egrep is identical to calling grep -E.

    That may get you a little performance increase. If you can look for fixed strings rather than regular expressions, that might also help. You can tell grep to look for a fixed string with the -F option:

    grep -F "id='%20or" apache.log
    

    But using fixed strings you lose a lot of flexibility.

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