Question

I need to parse content.xml file in XMind package.
File looks like this

<xmap-content xmlns="urn:xmind:xmap:xmlns:content:2.0" xmlns:fo="http://www.w3.org/1999/XSL   /Format" xmlns:svg="http://www.w3.org/2000/svg" xmlns:xhtml="http://www.w3.org/1999/xhtml" xmlns:xlink="http://www.w3.org/1999/xlink" version="2.0">

   <sheet id="sdfasdfsdf">
      <title> Sheet1 </title>
   </sheet>

   <sheet id="fgasdfgasr">
       <title> Sheet2 </title>
   </sheet>
<xmap-content>

I need to get list of title of all sheets.

I am using XPathExpression expr = navigator.Compile("//sheet");
but i guess its not working
what to do. any suggestion or code will do.
thnx in advance.

Answer 1

Your XML has defined default namespace: urn:xmind:xmap:xmlns:content:2.0. So you need to pass it to your XML engine with prefix, then use expression:

//ns:sheet

or another way:

//*[local-name() = 'sheet']