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Home/ Questions/Q 1002667
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T07:51:45+00:00 2026-05-16T07:51:45+00:00

I need to parseFloat this then to replace the dot with a comma: sum=<?php

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I need to parseFloat this then to replace the dot with a comma:

sum="<?php echo substr($_tarif_membre,0,-2).'.'.substr($_tarif_membre,-2,2) ?>" *  $('#tarif_membre').val()
total_total= sum.replace('.',',')
$('#total_total').val(sum)

if i dont multiply the php echoed variable by $('#tarif_membre').val() it will still show the result as a float:12.00 (as it is echoed from php) but if i multiply by $('#tarif_membre').val() the result will show 12, why? and why does the replace method does not work(i need to show comma separated values)

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  1. Editorial Team
    Editorial Team
    2026-05-16T07:51:46+00:00Added an answer on May 16, 2026 at 7:51 am

    I think this is what you’re trying to do:

    var sum = 12.00 * parseFloat($('#tarif_membre').val());
    total_total= sum.toFixed(2).replace('.',',');
    $('#total_total').val(total_total);
    

    You can try it out here.

    You should leave off the quotes since it’s a number, then parseFloat() the #tarif_membre .val(), since that will be a string, then they key to mainain decimal places for money here is calling .toFixed() on that float, this will get you "12.00", a string. You can them replace the . for a , (for international formatting I’m guessing?) Then I’m sticking that result into the #total_total, though this piece I’m unsure on.

    For the other question, why doesn’t .replace() work? It’s because in your code it was a float, not a string, and only strings have the replace method.

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