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Editorial Team
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Asked: 2026-06-03T08:54:37+00:00

I need to pass a dictionary from a python script to a Django app.

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I need to pass a dictionary from a python script to a Django app. Therefore I’m using the following:

def sendDataToApp(rssi_readings):
        url = 'http://localhost:8000/world/rssi_import'
        data = urllib.urlencode(rssi_readings)
        req = urllib2.Request(url, data)
        response = urllib2.urlopen(req)

The rssi_readings is the actual dictionary. Now in my Django app I have an url set up and do have a view defined as follows:

def rssi_import(request, rssi_readings):
    print "Test"
    cache.set('rssi_angle_reading', rssi_readings)
    return HttpResponse("Data submitted")

I’m not even seeing the print, so I think the server can’t handle the data. After that I want to store the data in a cache, which shouldn’t be a problem.

My dev server is up and running, but when I run the script I get an HTTP ERROR 500 with the following:

  File "autoorientation.py", line 245, in <module>
    main()
  File "autoorientation.py", line 241, in main
    sendDataToApp(rssi_readings)
  File "autoorientation.py", line 199, in sendDataToApp
    response = urllib2.urlopen(req)
  File "/usr/lib/python2.7/urllib2.py", line 126, in urlopen
    return _opener.open(url, data, timeout)
  File "/usr/lib/python2.7/urllib2.py", line 406, in open
    response = meth(req, response)
  File "/usr/lib/python2.7/urllib2.py", line 519, in http_response
    'http', request, response, code, msg, hdrs)
  File "/usr/lib/python2.7/urllib2.py", line 444, in error
    return self._call_chain(*args)
  File "/usr/lib/python2.7/urllib2.py", line 378, in _call_chain
    result = func(*args)
  File "/usr/lib/python2.7/urllib2.py", line 527, in http_error_default
    raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 500: INTERNAL SERVER ERROR

I was hoping anyone can tell me what the problem is? Even trying to post a simple string didn’t work. Thank you!!!

EDIT:

Here is my url.py. I have it split up in 2 files, but this should be the important one:

from django.conf.urls.defaults import patterns, include, url

urlpatterns = patterns('world.views',

    url(r'^$', 'index'),
    url(r'^setup/$', 'setup'),
    url(r'^redoscan/$', 'redoScan'),
    url(r'^rssi_import/$', 'rssi_import'),
)

EDIT2:

Ok, I have just tried to not send the data in the request from the script and now I actually get something. The dev server says:

[02/May/2012 15:32:46] "GET /world/rssi_import HTTP/1.1" 301 0
[02/May/2012 15:32:46] "GET /world/rssi_import/ HTTP/1.1" 200 14

So I’m very sure that the script works and my urls to, but somehow the stupid thing doesn’t know what to do with the data.

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1 Answer

  1. Editorial Team

    Ok, I finally figured it out.

    @Dan H You were right with the trailing slash, it actually made it big difference. Once removed I actually got a 403 error.

    After checking out with I got an 403 error I found something about CSRF, just as @Aleksej Vasinov already mentioned in one of his comments. I actually didn’t even know I was using that, but it seems to be almost the standard way in the settings file. I now have an CSRF exempt for this specific view and everything works fine.

    I can now post data and am very happy. Thank you for all your great ideas. I’ll be back on stackoverflow. 🙂

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