I need to perform a find and replace using XSLT 1.0 which is really suited to regular expressions. Unfortunately these aren’t available in 1.0 and I’m also unable to use any extension libraries such as EXSLT due to security settings I can’t change.
The string I’m working with looks like:
19;#John Smith;#17;#Ben Reynolds;#1;#Terry Jackson
I need to replace the numbers and ; # characters with a ,. For example the above would change to:
John Smith, Ben Reynolds, Terry Jackson
I know a recursive string function is required, probably using substring and translate, but I’m not sure where to start with it.
Does anyone have some pointers on how to work this out? Here’s what I’ve started with:
<xsl:template name="TrimMulti">
<xsl:param name="FullString" />
<xsl:variable name="NormalizedString">
<xsl:value-of select="normalize-space($FullString)" />
</xsl:variable>
<xsl:variable name="Hash">#</xsl:variable>
<xsl:choose>
<xsl:when test="contains($NormalizedString, $Hash)">
<!-- Do something and call TrimMulti -->
</xsl:when>
</xsl:choose>
</xsl:template>
I’m hoping you haven’t simplified the problem too much for asking it on SO, because this shouldn’t be that much of a problem.
You can define a template and recursively call it as long as you keep the input string’s format consistent.
For example,
I tested this template out with the following call:
And got the following output:
Which seems to be what you’re after.
The explanation of what it is doing is easy to explain if you’re familiar with functional programming. The
InputStringparameter is always in the form[number];#[name];#[rest of string]. Each call of theTrimMultitemplate chops off the[number];#part and prints off the[name]part, then passes the remaining expression to itself recursively.The base case is when
InputStringis in the form[number];#[name], in which case theRemainingStringvariable won’t contain;#. Since we know this is the end of the input, we don’t output a comma this time.