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Home/ Questions/Q 6049843
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T07:37:19+00:00 2026-05-23T07:37:19+00:00

I need to perform several copy commands on a remote location (using ssh cp

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I need to perform several copy commands on a remote location (using ssh “cp blah blah2”). Instead of having a separate ssh connection for each command, I would like to do something like:

dirs=(dir1 dir2 dir3)
for dir in ${dirs[*]} ; do echo $dir; done
ssh user@server "for dir in ${dirs[*]}; do echo $dir; cp some/file.txt /home/user/$dir/; done"

But even though the first echo prints all three dirs, the echos performed on the remote server are all equal to the last dir value (“dir3”). I don’t understand what I’m doing wrong, or why it’s printing three echos (and doing three copies), when it’s only using the same value. I guess it has something to do with when the variables are expanded (locally or remotely)…

I’ve tried using dirs=”dir1 dir2 dir3″, @ instead of *, quotings, but I haven’t been able to find a combination that works.

Anyone have any experience with this problem? 🙂

Cheers,
Svend.

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  1. Editorial Team
    Editorial Team
    2026-05-23T07:37:20+00:00Added an answer on May 23, 2026 at 7:37 am

    The for loop you execute before calling ssh creates a $dir varible and your shell expands it, so you are actually executing:

        ssh user@server "for dir in dir1 dir2 dir3; do echo dir3; cp some/file.txt /home/user/dir3/; done"
    

    You should escape $ to avoid shell expansion. Try:

    dirs="dir1 dir2 dir3"
    ssh user@server "for dir in $dirs ; do echo \$dir; cp some/file.txt /home/user/\$dir/; done"
    

    In this example, $dirs is a local variable and $dir is a remote variable. Your shell will replace $dirs in your command BEFORE executing ssh, so you will be really executing:

    ssh user@server "for dir in dir1 dir2 dir3; do echo \$dir; cp some/file.txt /home/user/\$dir/; done"
    
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