Question

I need to print a float value in area of limited width most efficiently. I’m using an NSNumberFormatter, and I set two numbers after the decimal point as the default, so that when I have a number like 234.25 it is printed as is: 234.25. But when I have 1234.25 I want it to be printed as: 1234.3, and 11234.25 should be printed 11234.

I need a maximum of two digits after the point, and a maximum of five digits overall if I have digits after the point, but it also should print more than five digits if the integer part has more.

I don’t see ability to limit the total number of digits in NSNumberFormatter. Does this mean that I should write my own function to format numbers in this way? If so, then what is the correct way of getting the count of digits in the integer and fractional parts of a number? I would also prefer working with CGFLoat, rather than NSNumber to avoid extra type conversions.

Answer 1

Here is how I implemented this in my code. I don’t know how efficient it is, I hope not bad.

So I create a global NSNumberFormatter

NSNumberFormatter* numFormatter; 

and initialize it somewhere:

numFormatter=[[NSNumberFormatter alloc]init];

Then I format number with the following function:

- (NSString*)formatFloat:(Float32)number withOptimalDigits:(UInt8)optimalDigits maxDecimals:(UInt8)maxDecimals
{
    NSString* result;
    UInt8 intDigits=(int)log10f(number)+1;
    NSLog(@"Formatting %.5f with maxDig: %d maxDec: %d intLength: %d",number,optimalDigits,maxDecimals,intDigits);  

    numFormatter.maximumFractionDigits=maxDecimals;
    if(intDigits>=optimalDigitis-maxDecimals) {
        numFormatter.usesSignificantDigits=YES;
        numFormatter.maximumSignificantDigits=(intDigits>optimalDigits)?intDigits:optimalDigits;
    } else {
        numFormatter.usesSignificantDigits=NO;
    }
    result = [numFormatter stringFromNumber:[NSNumber numberWithFloat:number]];

    return result;
}