Question

I need to print a received parameter at the end of every line… Here is what I did:

Printing info WITHOUT user:
CODE

user=$1
while read line; do
       linearr=($line)
       echo "${linearr[2]} ${linearr[0]} ${linearr[3]}"
done

OUTPUT:

b name2 5
c name3 2
a name1 0

Printing info WITH user at the end of each line:
CODE:

user=$1
while read line; do
       linearr=($line)
       echo "${linearr[2]} ${linearr[0]} ${linearr[3]} $user"
done

OUTPUT:

omare2 5
omare3 2
omare1 0

If I print the user (echo $user) it prints normally the name (omar)…
Why is this happening?

Answer 1

Most likely ${linearr[3]} ends with a \r. ($user could also start with that char.)

(This could happen if you’re redirecting from a file with Windows-type line endings \r\n.)