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Editorial Team
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Asked: 2026-05-20T10:27:49+00:00

I need to print out a second array, that takes the numbers from the

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I need to print out a second array, that takes the numbers from the first array. The second array will only print the number once if it has a duplicate. The code I have now prints the last number of the first array 20 times…. I can’t for the life of me figure out how to do this. I hate coming here with simple homework questions but the tutor is no help. If you can help me, please include some comments with what your doing, I want to learn this!

<html>
<head>
<title> HW 10.12 </title>
<script type="text/javascript">

var array=new Array(19);
var array2 =new Array();

for(var j=0; j< array.length; j++)
{
array[j]=Math.floor(10 + Math.random()*100);
}

for (var i=0; i < array.length; i++)

for(var k=0; k < array.length; k++)
{ 
if (array2[k] != array[i])
{ 
array2[k] = array[i];
}}


document.writeln(array2)

</script>
</head>
<body>
</body>
</html>
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1 Answer

  1. Editorial Team

    Change your javascript to as follows:

    var array = new Array(19);
var array2 = new Array();

for (var j = 0; j < array.length; j++) {
    array[j] = Math.floor(10 + Math.random() * 100);
}

var isDuplicate = false;    
for (var i = 0; i < array.length; i++) {
    isDuplicate = false;
    for (var k = 0; k < array.length; k++) {
        if (array2[k] == array[i]) { //Check if this current value of array1 exists in array2
         //If yes then we should ignore this value
         // hence mark isDuplicate as true.
          isDuplicate = true; 
          break; //Break from loop as we don't need to check any further
        }

    }
    if(!isDuplicate ) //if isDuplicate is not true this value is unique. Push it to array2
       array2.push(array[i]); 
}

document.writeln(array2)
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