Question

I need to push a hash into array only if it doesn’t contain the hash that i want to add.
For example i have an array of hashes :

var someArray = [
        {field_1 : "someValue_1", field_2 : "someValue_2"},
        {field_1 : "someValue_3", field_2 : "someValue_4"},
        {field_1 : "someValue_5", field_2 : "someValue_6"}
    ]

The value

{field_1 : "someValue_1", field_2 : "someValue_2"}

should not be pushed into array as it is already there, but the value

{field_1 : "someValue_7", field_2 : "someValue_8"}

should, as the array does’t contain such value.

Is there any way to do it using jQuery?

Now i’m just using $.each loop and check if the array contains some hash. If it does i trigger a flag. But i don’t like this solution.

Answer 1

1. create custom prototype to check the presence of object in the array. Please check the prototype design below.

Array.prototype.contains=function(x){
 for(i in this){
   if((x.field_1==this[i].field_1)&&(x.field_2==this[i].field_2))
     return true;  
 }
 return false;
}

1. Using above prototype, you can check if object present in an array.

 var someArray = [
        {field_1 : "someValue_1", field_2 : "someValue_2"},
        {field_1 : "someValue_3", field_2 : "someValue_4"},
        {field_1 : "someValue_5", field_2 : "someValue_6"}
    ];

var a1={field_1 : "someValue_1", field_2 : "someValue_2"};
var a2={field_1 : "someValue_7", field_2 : "someValue_8"};

if(!someArray.contains(a1))   someArray.push(obj);  // it will NOT BE pushed
if(!someArray.contains(a2))   someArray.push(obj); // it will be pushed