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Home/ Questions/Q 6171597
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Editorial Team
  • 0
Editorial Team
Asked: May 23, 20262026-05-23T23:14:36+00:00 2026-05-23T23:14:36+00:00

I need to put to parameter in DATA , how can I do this

  • 0

I need to put to parameter in DATA , how can I do this ?

I try that , but that did’nt work :

 data: dataString + form_data ,

My complete code:

        $(".edit_tr").click(function()
{
var ID=$(this).attr('id');
$("#first_"+ID).hide();
$("#last_"+ID).hide();
$("#first_input_"+ID).show();
$("#last_input_"+ID).show();
}).change(function()
{
var ID=$(this).attr('id');
var first=$("#first_input_"+ID).val();
var last=$("#last_input_"+ID).val();
var dataString = 'id='+ ID +'&firstname='+first+'&lastname='+last;
$("#first_"+ID).html('<img src="load.gif" />');


if(first.length && last.length>0)


{
var form_data = {
    ci_csrf_token: $.cookie("ci_csrf_token"),

}

$.ajax({
type: "POST",
url:'http://' + document.domain + '/school/teachers/editscore/',
//data: dataString,
data: form_data,


//cache: false,
    success: function(html)
    {

        $("#first_"+ID).html(first);
        $("#last_"+ID).html(last);
        }
});
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T23:14:36+00:00Added an answer on May 23, 2026 at 11:14 pm

    You pass data as a json object

    var form_data = '&ci_csrf_token='+ $.cookie("ci_csrf_token");
    
        };
    $.ajax({
    type: "POST",
    url:'http://' + document.domain + '/school/teachers/editscore/',
    //data: dataString,
    data: dataString + form_data,
    processData: false,
    //cache: false,
        success: function(html)
        {
    
            $("#first_"+ID).html(first);
            $("#last_"+ID).html(last);
            }
    });
    
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