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Home/ Questions/Q 1073763
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T21:01:58+00:00 2026-05-16T21:01:58+00:00

I need to read a file in my code. It physically resides here: C:\eclipseWorkspace\ProjectA\src\com\company\somePackage\MyFile.txt

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I need to read a file in my code. It physically resides here:

C:\eclipseWorkspace\ProjectA\src\com\company\somePackage\MyFile.txt

I’ve put it in a source package so that when I create a runnable jar file (Export->Runnable JAR file) it gets included in the jar. Originally I had it in the project root (and also tried a normal sub folder), but the export wasn’t including it in the jar.

If in my code I do:

File myFile = new File("com\\company\\somePackage\\MyFile.txt");

the jar file correctly locates the file, but running locally (Run As->Java Main application) throws a file not found exception because it expects it to be:

File myFile = new File("src\\com\\company\\somePackage\\MyFile.txt");

But this fails in my jar file. So my question is, how do I make this concept work for both running locally and in my jar file?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T21:01:59+00:00Added an answer on May 16, 2026 at 9:01 pm

    Use ClassLoader.getResourceAsStream or Class.getResourceAsStream. The main difference between the two is that the ClassLoader version always uses an “absolute” path (within the jar file or whatever) whereas the Class version is relative to the class itself, unless you prefix the path with /.

    So if you have a class com.company.somePackage.SomeClass and com.company.other.AnyClass (within the same classloader as the resource) you could use:

    SomeClass.class.getResourceAsStream("MyFile.txt")
    

    or

    AnyClass.class.getClassLoader()
                  .getResourceAsStream("com/company/somePackage/MyFile.txt");
    

    or

    AnyClass.class.getResourceAsStream("/com/company/somePackage/MyFile.txt");
    
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